1377087 - backslash 's' (\s) fails to match non-breacking whitespace (\u00a0) in Firefox ESR 52.2.0 regexp

Status: RESOLVED INVALID

(Core :: JavaScript Engine, defect)

Description

[Siltaer]

User Agent: Mozilla/5.0 (X11; Linux x86_64; rv:52.0) Gecko/20100101 Firefox/52.0
Build ID: 20170613225334

Steps to reproduce:

I tried to match a regexp against a string containing a \u00a0 (from converted   HTML entity).
The regexp was defined using '\s' to match every whitespaces.


Actual results:

The \u00a0 has not been matched.


Expected results:

It should have been matched as stated here : https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp
« \s : Matches a single white space character, including space, tab, form feed, line feed and other Unicode spaces. Equivalent to [ \f\n\r\t\v\u00a0\u1680\u2000-\u200a\u2028\u2029\u202f\u205f\u3000\ufeff]. For example, /\s\w*/ matches " bar" in "foo bar". »

I replaced my \s by a [\s\u00a0] and it worked.

Comment 1

[Tooru Fujisawa [:arai]]

Can you provide a standalone testcase?

the following code works as expected and it matches:
  "\xa0".match(/\s/)

Comment 2

[Siltaer]

Ok sorry, my bad.

I badly escaped my \s.