calling Firefox with -remote openurl() brings up Seamonkey's old "open" dialog, mentioning composer

RESOLVED WORKSFORME

Status

()

Firefox
Menus
RESOLVED WORKSFORME
14 years ago
7 years ago

People

(Reporter: Jeremy M. Dolan, Unassigned)

Tracking

Firefox Tracking Flags

(Not tracked)

Details

(Reporter)

Description

14 years ago
With Firebird running, send it the remote command "openurl()". That is, openurl
with a null argument. Firebird will open a dialog asking what file/URL you want
to load, and where (current, new window, new tab, or COMPOSER). I believe this
is about 12-month old UI from Seamonkey.

Previously, openurl() behavior was to load the current working directory in
Firebird, which was quite handy. (ie, file:///home/user).

Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.6b) Gecko/20031126 Firebird/0.7+
(Reporter)

Comment 1

14 years ago
The function that brings up this UI: OpenURLDialog(domWindow)

http://lxr.mozilla.org/seamonkey/source/xpfe/components/xremote/src/XRemoteService.cpp#205
Summary: calling Firebird with -remote openurl() brings up Seamonkey's old "open" dialog, mentioning composer → calling Firefox with -remote openurl() brings up Seamonkey's old "open" dialog, mentioning composer

Updated

12 years ago
Assignee: firefox → nobody
QA Contact: bugzilla → menus

Comment 2

7 years ago
This now produces this output in the terminal:

"Error: Failed to send command: 500 command not parseable"

Seems to address the issue raised in the original report: it doesn't bring up obsolete UI anymore.  If you want -remote openurl() to do something other than complain about invalid syntax, please feel free to file a bug for that.
Status: NEW → RESOLVED
Last Resolved: 7 years ago
Resolution: --- → WORKSFORME
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