Closed
Bug 339687
Opened 18 years ago
Closed 18 years ago
Regular expression test evaluates false once and then true for the same test
Categories
(SeaMonkey :: General, defect)
Tracking
(Not tracked)
People
(Reporter: carlosi, Unassigned)
Details
Attachments
(1 file)
|
491 bytes,
text/html
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Details |
User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.0.3) Gecko/20060426 Firefox/1.5.0.3
Build Identifier: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.0.3) Gecko/20060426 Firefox/1.5.0.3
When using test on a regular expression that tries to determine if a numeric value is valid or not, the test returns true the first time and false the second time, even when doing the same test on the same value.
Reproducible: Always
Steps to Reproduce:
1. Create a regular expression object as follows: regExp = /^-{0,1}\d*\.{0,1}\d+$/g;
2. execute at least twice and check the return of the test: regExp.test(50);
3.
Actual Results:
It first evaluates to true and then to false
Expected Results:
It should have evaluated to true both times.
You could create the following html file and open it with Mozilla to see the error:
------------------ HTML File begins here --------------------
<html>
<head>
<title>Regular expression bug</title>
<script type="text/javascript">
function isDecimal(number)
{
var regExp = /^-{0,1}\d*\.{0,1}\d+$/g;
return regExp.test(number);
}
for (var i = 0; i < 2; i++)
{
if (!isDecimal(50))
alert('If this shows up, we have a bug');
else
alert('We should always get this message');
}
</script>
</head>
<body>
This page shows a Mozilla bug found when testing values using regular expressions
</body>
</html>
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Reporter | |
Comment 1•18 years ago
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Comment 2•18 years ago
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Actually, the JS Engine behaves like the ECMA spec describes it. Remove the /g from your regular expression and it should work like you want it.
*** This bug has been marked as a duplicate of 98409 ***
Status: UNCONFIRMED → RESOLVED
Closed: 18 years ago
Resolution: --- → DUPLICATE
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Description
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