395127 - uneval corrupts function having RegExp with unicode characters

Status: RESOLVED DUPLICATE of bug 375641

(Core :: JavaScript Engine, defect)

Description

[Biju]

I found it is OK to use unicode characters in RegExp 
with out escaping like \u9999.
But if you uneval the function and re-eval it, 
it get corrupted.

example:-
   function a() {return /ഷസ/;}

becomes
   function a() {return /78/;}

But if unicode characters in RegExp are escaped 
Like
   function c() {return /\u0D37\u0D38/;}

this  cont cause any problem
you get eval(uneval()) as the same
   function c() {return /\u0D37\u0D38/;}


========= test case ======
s=[];
function a() {return /ഷസ/;}
s.push(['return val of a ......', a()]);
b = uneval(a)
s.push(['uneval a .............',b]);
eval(b);
s.push(['return after re-eval..',a()]);
function c() {return /\u0D37\u0D38/;}
s.push(['uneval c .............',uneval(c)]);
function d() {return "ഷസ";}
s.push(['uneval a .............',uneval(d)]);

s.join('\n');


========= current output ======
Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9a8pre) 
Gecko/2007090304 Minefield/3.0a8pre

return val of a ......,/ഷസ/
uneval a .............,function a() {return /78/;}
return after re-eval..,/78/
uneval c .............,function c() {return /\u0D37\u0D38/;}
uneval a .............,function d() {return "\u0D37\u0D38";}