452188 - |watch| and |delete| causes setter to act like a watchpoint (return value becomes new value)

Status: RESOLVED WORKSFORME

(Core :: JavaScript Engine, defect)

Description

[Jesse Ruderman]

x = 1;
__defineSetter__('x', function(){return 2;});
watch('x', function(){return 3;});
delete x;
x = 5;
print("x is " + this.x);

x is 2

This doesn't make sense to me.  Is the brief existence of a watchpoint somehow making the setter gain watchpoint semantics?

Comment 1

[Jason Orendorff [:jorendorff]]

Now it says "x is 5".