Closed
Bug 546509
Opened 14 years ago
Closed 14 years ago
with-param doesn't work with apply-templates
Categories
(Core :: XSLT, defect)
Tracking
()
RESOLVED
INVALID
People
(Reporter: dfradin, Unassigned)
Details
Attachments
(2 files)
User-Agent: Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.1.7) Gecko/20100106 Ubuntu/9.10 (karmic) Firefox/3.5.7 Build Identifier: Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.1.7) Gecko/20100106 Ubuntu/9.10 (karmic) Firefox/3.5.7 When trying to pass parameters, by using the element <xsl:with-param/>, to templates applied through the element <xsl:apply-templates>, said parameters' values are simply ignored by the templates involved, that systematically fall back to default values, if any. Reproducible: Always Steps to Reproduce: 1.Create a trivial XML file, with just a root element and a few children elements. Example: <?xml version="1.0" encoding="UTF-8"?> <root> <child>value1</child> <child>value2</child> <child>value3</child> </root> 2.Create a XSLT sheet designed to turn the XML file into a HTML file with an unordered list containing as items the values of the children elements, using the apply-templates element to process the latter ones, with a parameter of which value will be appened to each of them, between parentheses. Example : <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html"/> <xsl:template match="/"> <html> <head> <title>trivial example</title> </head> <body> <ul> <xsl:apply-templates select="root"> <xsl:with-param name="thingy" select="'stuff'"/> </xsl:apply-templates> </ul> </body> </html> </xsl:template> <xsl:template match="child"> <xsl:param name="thingy"/> <li><xsl:value-of select="."/>(<xsl:value-of select="$thingy"/>)</li> </xsl:template> </xsl:stylesheet> 3. Attach the stylesheet to the XML file with a proper <?xml-stylesheet?> declaration, then display the XML file in, for example, FireFox. Actual Results: The browser displays the following: * item1() * item2() * item3() * item4() Expected Results: * item1(stuff) * item2(stuff) * item3(stuff) * item4(stuff) This is a standard compliance issue, since the <xsl:apply-templates> element should be able to take parameters to transmit to its templates, as specified in the W3C recommendation for XSLT 1.0.: http://www.w3.org/TR/xslt#section-Passing-Parameters-to-Templates I tested my example with xsltproc, which gave the expected result. For information: there's no such issue with the <xsl:call-template> element, whith which parameters work quite fine.
Could you attach the testcase as a file. That will allow for much easier testing.
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Reporter | |
Comment 2•14 years ago
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Reporter | |
Comment 3•14 years ago
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Ah, I see the bug in the stylesheet now. The <xsl:apply-templates> doesn't actually directly apply the template that accepts a parameter. You are trying to apply templates to the <root> element. However there is no template in your stylesheet that applies to the <root> element. Thus a default template is applied. This default template applies templates to all children, however it does not forward any parameters. This is all per spec. If you change it to <xsl:apply-templates select="root/child"> then it should work.
Status: UNCONFIRMED → RESOLVED
Closed: 14 years ago
Resolution: --- → INVALID
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Description
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