624723 - Get visited sites using getComputedStyle and CSS

Status: RESOLVED DUPLICATE of bug 147777

(Core :: CSS Parsing and Computation, defect)

Description

[Simon Roesler]

User-Agent:       Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US) AppleWebKit/534.10 (KHTML, like Gecko) Chrome/8.0.552.224 Safari/534.10
Build Identifier: Mozilla/5.0 (Windows; U; Windows NT 5.1; de; rv:1.9.2.13) Gecko/20101203 Firefox/3.6.13

With using the Javascript code getComputedStyle and the CSS-Visited Tag it´s possible to check wheater an user has visited a specific website.
The Code to Check:
if(window.getComputedStyle(document.getElementById("check"),null).getPropertyValue("display") == "inline")

And the CSS for this:
div.history a { display: none;}
div.history a:visited { display: inline;}

Later I saw that it should already be fixed but it isn´t.

Reproducible: Always

Steps to Reproduce:
1. Visit a site
2. enter the site adress in the textbox at the included site
3. Click Check and see what happen
Actual Results:  
It says weather a site was visited or not.

Expected Results:  
There shouldn´t be an ability of checking this with javascript.

I read, that this is already solved but with my code (I don´t know what i did different) it´s working in my firefox.

Comment 1

[Boris Zbarsky [:bzbarsky]]

> I read, that this is already solved 

It's solved in Firefox 4.

Comment 2

[Brandon Sterne (:bsterne)]

(In reply to comment #1)
> It's solved in Firefox 4.

In bug 147777.