Hey Ben, maybe i'm doing something wrong here . . . If is set a radio like so: document.getElementById('aRadio').checked=true; the previously checked radio remains checked and i have two checked radios . . . So i ended up doing this for it to work: var child=document.getElementById('radioGroupId').childNodes; for(n=0;n<child.length;n++) child[n].removeAttribute('checked'); document.getElementById('targetRadio').checked=true; Thanks pete
By the way, you can use the .selectedItem setter of <radiogroup> to get the result you want (i.e., it will remove checked status from the current selectedItem, and set it on the new selectedItem (automagic mutual exclusion)): var radiogroup = document.getElementById("aGroup"); radiogroup.selectedItem = document.getElementById("aRadio"); (But this bug is really about a possible change to the binding that might make individual <radio> elements "aware" of their containment in the <radiogroup>).
Exactly John, thanks. I am just use to html behavior. You set a child to checked and their siblings are aware of the change. pete
I'm not setting the selectedItem internally. this is wrong. accepting.
Status: NEW → ASSIGNED
Target Milestone: --- → M20
18 years ago
Target Milestone: --- → mozilla1.0
Assignee: ben → blakeross
Status: ASSIGNED → NEW
You can't set .checked (which is now .selected) anymore. The only proper way to do it is to set the radiogroup's selectedItem. Marking invalid.
Status: NEW → RESOLVED
Last Resolved: 18 years ago
Resolution: --- → INVALID
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