Closed Bug 620406 Opened 14 years ago Closed 14 years ago

Constant folding branch condition leads to assert in Assembler.cpp

Categories

(Core Graveyard :: Nanojit, defect, P2)

defect

Tracking

(Not tracked)

RESOLVED FIXED
flash10.1.x-Spicy

People

(Reporter: edwsmith, Unassigned)

References

Details

(Whiteboard: fixed-in-nanojit, fixed-in-tracemonkey)

Attachments

(1 file, 1 obsolete file)

Simple test: test.as: function test(s:String) { var x, y return x[y>>5] <--- x is undefined, therefore branch-to-UPE is a jump. } $ asc test.as $ avmshell -Dverifyonly test.abc Assertion failure: !ins->callInfo()->_isPure || ins->isExtant() (.../nanojit/Assembler.cpp:2043) The cause is related to: 1. AvmCore::integer() is marked pure, but should not be. See bug 620403. 2. The unconditional branch makes the >> expresion dead, which should leave the implicit integer(y) call dead, but doesn't... the assert fires because the seemingly dead expression isn't dead (isExtant()==false, but isLive() == true).
Here is the relevant LIR. Y is the undefined constant (4). For the y>>5 expression, we generate a pure call to integer(4), then right shift it. integer1 = calli.none #integer ( immi5/*4*/ ) rshi1 = rshi integer1, immi8/*5*/ Then we unconditionally branch, and emit some unreachable code, too: j -> unpatched getpropertylate_i1 = calli.all #getpropertylate_i ( parami1 immi5/*4*/ rshi1 ) The unreachable reference to rshi1 makes it "live" but doesn't assign it to any register. In assembler.gen, we have: case LIR_rshi: ins->oprnd1()->setResultLive(); // sets integer1 live ins->oprnd2()->setResultLive(); // sets immi5 (4) live if (ins->isExtant()) // false asm_arith(ins); // skipped break; And the code for LIR_calli for a pure call to integer(): case LIR_calli: for (int i = 0, argc = ins->argc(); i < argc; i++) ins->arg(i)->setResultLive(); // It must be impure or pure-and-extant -- it couldn't be // pure-and-not-extant, because there's no way the codegen // for a call can be folded into the codegen of another // LIR instruction. NanoAssert(!ins->callInfo()->_isPure || ins->isExtant()); asm_call(ins); break; The assert imples that the only reason an instruction could be live but !extant, is if it was folded into another instruction. However, in this case, nothing was folded - the rshi wasn't folded, it was in dead code, so its register assignments were cleared, but its 'live' bit wasn't cleared. We didn't assert in LIR_rshi because it could have been folded in other scenarios. Possible bugs: 1. handling of dead paths (code after an unconditional jump or after a return) doesn't clear live bits. (How could it? how do we know the instruction really is live?) 2. The assert is too strong on LIR_calli. A call to a pure pure function should behave just like a plain instruction. Folding isn't the only way a plain instruction can be !extant, therefore calls are subject to the same situations. Relaxing the assert is easy. Rethinking "live" vs "extant" doesn't seem quite as easy. This bug might be related to bug 607816
> 2. The assert is too strong on LIR_calli. This is a patch that fixes bug #2, if we decide it's really a bug. Rick - can you figure out if this is in any way related to bug 607816? Nick - looking for input... whats the bug, really? A third possible bug is that our frontend is emitting dead code. But, I think we've had a few precedents where we decided the backend should "just work" even if the LIR code is dumb. > 1. handling of dead paths (code after an unconditional jump or after > a return) doesn't clear live bits. Unreachable code is code that follows an unconditional branch, without a label: j -> somewhere /* no label */ unreachable code Since we assemble bottom-up, we dont know if some code is unreachable until we see that unconditional branch. By then, there could be many instructions we have marked (live=1, extant=1). Anything that spilled will stay extant at this point. (we clear register assignments but we dont clear the inAr flag). So, the only instructions that get into this (live=1, extant=0) state are ones that haven't spilled. The complexity of true unreachable code elimination seems beyond the scope of the backend, without a lot of work.
Assignee: nobody → edwsmith
Attachment #498757 - Flags: feedback?(rreitmai)
Attachment #498757 - Flags: feedback?(nnethercote)
Component: JIT Compiler (NanoJIT) → Nanojit
Priority: -- → P2
Product: Tamarin → Core
QA Contact: nanojit → nanojit
Target Milestone: --- → flash10.1.x-Spicy
Flags: in-testsuite?
Comment on attachment 498757 [details] [diff] [review] Relax the assert in case LIR_call, and don't emit dead pure calls. >--- a/nanojit/Assembler.cpp Sat Dec 18 16:56:53 2010 -0500 >+++ b/nanojit/Assembler.cpp Mon Dec 20 11:53:54 2010 -0500 >@@ -2036,12 +2036,14 @@ > countlir_call(); > for (int i = 0, argc = ins->argc(); i < argc; i++) > ins->arg(i)->setResultLive(); >- // It must be impure or pure-and-extant -- it couldn't be >- // pure-and-not-extant, because there's no way the codegen >- // for a call can be folded into the codegen of another >- // LIR instruction. >- NanoAssert(!ins->callInfo()->_isPure || ins->isExtant()); >- asm_call(ins); >+ // Calls are not folded into other instructions, >+ // but they can be referenced by simple instructions that >+ // are foldable, such as LIR_rshi. This can leave a pure >+ // call live but not extant. We treat it like any other >+ // instruction in that situation. >+ if (!ins->callInfo()->_isPure || ins->isExtant()) { >+ asm_call(ins); >+ } > break; I didn't think of the case where the call's result was only used in code that was dead due to an always-taken branch. You are right, detecting dead code of this sort is difficult with our backwards assembly pass, so removing the assert is the best way to go. But I think the comment isn't quite right because it doesn't mention the dead code. I suggest: You might think that a call cannot be pure-and-not-extant, because there's no way the codegen for a call can be folded into the codegen of another LIR instruction. However, it's possible that a pure call, C, has a result that is only be used (directly or indirectly) in a section of code that is dead due to an always-taken branch. C is dead, but the assembly pass doesn't realize is dead. So C may end up non-extant, in which case we don't generate code for it. See bug 620406 for an example. It would also be worth adding a comment to isLive() to indicate that it is conservative, ie. it can say that an instruction is live when it's really dead due to always-taken branches.
Attachment #498757 - Flags: feedback?(nnethercote) → feedback+
Agreed. Assembler's notion of "live" really just means an instruction has been used by another instruction the assembler visited. The whole method could be unreachable, for all the assembler knows -- reachability is just not part of the equation at all.
Blocks: 620676
Updated the comment, added comment to LIns.isLive(). Passed acceptance runs on tamarin.
Attachment #499135 - Flags: review?(nnethercote)
Attachment #498757 - Attachment is patch: false
Attachment #498757 - Attachment is obsolete: true
Attachment #498757 - Attachment is patch: true
Attachment #498757 - Flags: feedback?(rreitmai)
Comment on attachment 499135 [details] [diff] [review] (v2) Relax the assert in case LIR_call, and don't emit dead pure calls. > // Generally, void instructions (statements) are always live and > // non-void instructions (expressions) are live if used by another > // live instruction. But there are some trickier cases. >+ // Any non-void instruction can be marked isResultLive=1 even >+ // when it is unreachable. The assembler marks it live if it >+ // sees any uses, regardless of whether those uses are in reachable >+ // code or not. Nit: Can you clarify slightly, eg. "when it is unreachable, eg. due to an always taken branch"?
Attachment #499135 - Flags: review?(nnethercote) → review+
sure, no problem.
Whiteboard: fixed-in-nanojit
Assignee: edwsmith → nobody
Whiteboard: fixed-in-nanojit → fixed-in-nanojit, fixed-in-tracemonkey
Status: NEW → RESOLVED
Closed: 14 years ago
Resolution: --- → FIXED
Product: Core → Core Graveyard
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