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People
(Reporter: brbaker, Unassigned)
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(Blocks: 1 bug)
Details
ecma262, s15.8.2.15 round (x) Returns the Number value that is closest to x and is equal to a mathematical integer. If two integer Number values are equally close to x, then the result is the Number value that is closer to +INFINITY. If x is already an integer, the result is x.  If x is 0, the result is 0. Math.round(0); > 0 (should be 0) Infinity/Math.round(0) > +Infinity (should be Infinity)
Flags: intestsuite?
Flags: flashplayertriage+
Flags: flashplayerqrb?
Flags: flashplayerbug
(Reporter)  
Comment 1•7 years ago


The testcase ecma3/Number/e15_8_2_15.as "Infinity/Math.round(0)" is actually checking for +Infinity instead of Infinity
(Reporter)  
Comment 2•7 years ago


Another point in the specification that is not handled properly is:  If x is less than 0 but greater than or equal to 0.5, the result is 0. Math.round(0.49); > 0 (should be 0) Infinity/Math.round(0.49) > +Infinity (should be Infinity)
Summary: Math.round() does not handle 0 properly → Math.round() does not handle 0 and 0.5 properly
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