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Re-directed to




18 years ago
16 years ago


(Reporter: bugzilla, Assigned: darin.moz)


Windows NT

Firefox Tracking Flags

(Not tracked)





18 years ago
From Bugzilla Helper:
User-Agent: Mozilla/5.0 (Windows; U; WinNT4.0; en-US; 0.8) Gecko/20010215
BuildID:    2001021508

Type "" into the address box. Type Enter.
Ultimately the page is loaded. I'm not German, but in the UK
expecting to go to the site

If this is some DNS lookup problem it seem specific to Mozilla. Loading IE and
repeating takes me to the the expected English language site.

Reproducible: Always
Steps to Reproduce:
See description

Actual Results:  See description

Expected Results:  See description
I get something like

HTTP/1.0 302 Moved Temporarily

even when I send a plain (without "User-Agent:")

GET / HTTP/1.0

So this looks not like a bug in Mozilla to me.
Maybe Google looks at your IP address and treats it wrong.
But I am German and the IP address I get by my ISP resolves to a *.de name.
Therefore it may be that Mozilla's UA string causes the error.

Reporter, have you tried this with cookies disabled? Google uses cookies.
Also, make sure you try with the same IP address in both Mozilla and IE (i.e.
use the same proxy configuration and don't cut the connection to your ISP
between both tries).

Comment 2

18 years ago
sounds like when we understand what's happening we'll resolve as invalid, 
although it is interesting and i'd like to know what's going on first...
Assignee: asa → darin
Component: Browser-General → Networking: HTTP
QA Contact: doronr → tever

Comment 3

18 years ago
Interesting, both .com and .de site's are located in the UK, on the same server.
Just try this to proof that:

ping you get a reply from
ping  you get a reply from

tracert and tracert ends at 
Also note that I don't get a HTTP/1.(0/1) 302 Moved Temporarily. And I did use a
protocol analyser for that. 

Reporter, can you attach your "tracert > file.txt" to this bug??

Comment 4

18 years ago
And make sure that you do the same for, thank you.  has CNAME has CNAME

Asking I get 5 nameservers for With all but the
last ( I get errors. has A

Comment 6

18 years ago
for me has CNAME but that doesn't matter
because it ends up at anyway. I'm unable to reproduce the DNS
errors here, so that might be related to local network routing in Germany.

Comment 7

18 years ago
Andreas, when do you see those errors? Can you attach a trace route output? 
When you resolve those addresses, where does it stop, what is the last address?
No problem with tracert. But I cannot connect to them on port 53 using tcp.
Not tried with udp.

Tried another thing: Connected explicitly to the 4 IP addresses, but using
"Host:" and without any "User-Agent:".
Got "200 OK" for, but a 302 redirecting to for the
other 3. My IP address was, resolving to (known as German).

If I do the same from my website located in Nevada i get a 200 for all 4.

I'm pretty sure now that this is a problem at Google.
Suggesting to mark this bug invalid.
Last Resolved: 18 years ago
Resolution: --- → INVALID
Got answer from Google:

Hi -

As you have noticed Google has recently started using IP-address detection to 
help our users find our foreign
destination sites.  Unfortunately, our IP-address detection is not perfect and 
you are being inappropriately
redirected.  We are working on the problem.  In the interim, you can regain your 
old experience by
simply clicking on the " [English]" link in the footer of the page.  
By clicking on this, Google will
note that you have opted out of the foreign domain site and you will no longer 
experience redirects.

We apologize for any inconvenience.

The Google Team

Resolving INVALID.

Comment 11

18 years ago
Hi, Google is attempting to redirect some users to a country-specific home page 
(German users get sent to, for example) base on the IP address. We had 
some bad data on a few subnets though, esp. some Class C blocks that UUNet uses 
in the UK. These problems should be fixed now--sorry that you got this bug 

Matt Cutts

Comment 12

16 years ago
Verified invalid.
QA Contact: tever → junruh
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